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A sample of 35 Kg of dry steam contains 0.7 Kg of water is in suspension, find its dryness fraction. 
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1 Answer

Mass of dry steam=35 kg

Mass water suspension=0.7 kg

Weight of wet steam=35+0.7=35.7 kg

So,

 Dryness fraction X=Actual mass of dry steam/ weight of wet steam

 = 35 / (35+0.7)

 =0.098039
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