Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it ... sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps Answer : (C) 128 kbps...
Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps Answer : Answer: Marks given to all...
A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps ...
What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps. ...
Four channels are multiplexed using TDM. If each channel sends 100 bytes/second and we multiplex 1 byte per channel, then the bit rate for the link is ............... (A) 400 bps (B) 800 bps (C) 1600 bps (D) 3200 bps Answer : (D) 3200 bps Answer: D Explanation: The multiplexer is shown in the Figure. Each frame carries 1 byte from each channel; the size of each frame, therefore, is 4 bytes, or 32 bits. Because each ... channel, the frame rate must be 100 frames per second. The bit rate is 100 32 = 3200 bps. ...
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