In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284
1 Answer
A)
Maximum mark consist of a three digit number let’s consider
Unit digit place is Z,ten's place digit is Y and hundred's place digit is X.
According to the question,
Y=x+z---------1
X+Y+Z=10, substitute equation 1
2y=10
Y=5
X+Z=5--------2
Number=100z+10y+x
100z+10y+x=100x+10y+z-297
99x-99z=297
X-Z=3---------3
Solve equation 2 and 3,
X =4,z=1
Original number =451=maximum mark
Total number of Mahi, Nitesh and Ritesh
=164/100×451=739.61
Required average =739.64/3=246.54~247.
Maximum mark consist of a three digit number let’s consider
Unit digit place is Z,ten's place digit is Y and hundred's place digit is X.
According to the question,
Y=x+z---------1
X+Y+Z=10, substitute equation 1
2y=10
Y=5
X+Z=5--------2
Number=100z+10y+x
100z+10y+x=100x+10y+z-297
99x-99z=297
X-Z=3---------3
Solve equation 2 and 3,
X =4,z=1
Original number =451=maximum mark
Total number of Mahi, Nitesh and Ritesh
=164/100×451=739.61
Required average =739.64/3=246.54~247.