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Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

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Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 
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Answer: D

 Let the marks secured by them be x and (x + 18)

 Then sum of their marks = x + (x + 18) = 2x + 18

 Given that (x + 18) was 72% of the sum of their marks

 =>(x+18) = 72/100(2x+18)

 =>(x+18) = 18/25(2x+18)

 => 25x + 450 = 36x + 324

 => 11x = 126  x = 11.45

 Then (x + 18) = 11.45 + 18 = 29.45

 Hence their marks are 11.45 and 29.45
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